JEE MAIN - Physics (2018 - 16th April Morning Slot - No. 5)
A ray of light is incident at an angle of 60o on one face of a prism of angle 30o. The emergent ray of light makes an angle of 30o with incident ray. The angle made by the emergent ray with second face of prism will be :
0o
90o
45o
30o
Forklaring
Given : $${i_1} = 60^\circ $$; $$A = 30^\circ $$
Then angle of deviation is given by
$$\delta = 1 - A = 60^\circ - 30^\circ = 30^\circ $$
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We know that,
$${i_1} + {i_2} = A + \delta \Rightarrow 60^\circ + {i_2} = 30^\circ + 30^\circ \Rightarrow {i_2} = 0$$
It means emergent ray leaves face AC normally.